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In this scenario, we can observe the application of combinatorics and probability theory. To determine the number of ways to form a committee of 3 members from a group of 10 people, we use combinations (denoted as C(n, k) = n! / [k!(n-k)!]), where n is the total number of people and k is the committee size. Here, C(10, 3) = 10! / [3!(10-3)!] = 120 ways to form the committee. However, if we consider a more complex situation where the order of selection matters (e.g., assigning specific roles), we would use permutations (P(n, k) = n! / (n-k)!), yielding 120
6 = 720 possible ordered arrangements. To calculate the probability of selecting a specific committee, say with members A, B, and C, we divide the number of favorable outcomes (1) by the total possible outcomes (720), resulting in a probability of 1/720. This scenario showcases how combinatorics helps count possibilities and probability quantifies the likelihood of specific outcomes in a set of choices.